y^4-y^2+2=0

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Solution for y^4-y^2+2=0 equation:


Simplifying
y4 + -1y2 + 2 = 0

Reorder the terms:
2 + -1y2 + y4 = 0

Solving
2 + -1y2 + y4 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -1y2 + -2 + y4 = 0 + -2

Reorder the terms:
2 + -2 + -1y2 + y4 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1y2 + y4 = 0 + -2
-1y2 + y4 = 0 + -2

Combine like terms: 0 + -2 = -2
-1y2 + y4 = -2

The y term is -1y2.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1y2 + 0.25 + y4 = -2 + 0.25

Reorder the terms:
0.25 + -1y2 + y4 = -2 + 0.25

Combine like terms: -2 + 0.25 = -1.75
0.25 + -1y2 + y4 = -1.75

Factor a perfect square on the left side:
(y2 + -0.5)(y2 + -0.5) = -1.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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